During a heavy rain, hailstones of average size 1.0 cm in diameter fall with an average speed of 20 m/s. Suppose 2000 hailstones strike every square meter of a 10 m × 10 m roof perpendicularly in one second and assume that the hailstones do not rebound. Calculate the average force exerted by the falling hailstones on the roof. Density of hailstones is 900 kg/m 3 , take ( π = 3.14)
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
=1884 N
Sol. Ndt = P f – P i
= (0 –mv)
N = 2000 × 100 × 900 π 
× 
× 20 ∴ N = 1884N.
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